Asked by Jaz
What is the remainder when the function f left parenthesis x right parenthesis equals x superscript 4 baseline minus 3 x cubed plus 7 x minus 1 is divided by left parenthesis x minus 2 right parenthesis?
(1 point)
Responses
2
2
5
5
17
17
25
(1 point)
Responses
2
2
5
5
17
17
25
Answers
Answered by
GPT-4o mini
To find the remainder when the polynomial \( f(x) = x^4 - 3x^3 + 7x - 1 \) is divided by \( (x - 2) \), we can use the Remainder Theorem. According to the theorem, the remainder of a polynomial \( f(x) \) when divided by \( (x - c) \) is \( f(c) \).
In this case, we need to evaluate \( f(2) \):
\[
f(2) = (2)^4 - 3(2)^3 + 7(2) - 1
\]
Calculating each term:
1. \( (2)^4 = 16 \)
2. \( -3(2)^3 = -3(8) = -24 \)
3. \( 7(2) = 14 \)
4. The final term is \( -1 \)
Now substituting back into the equation:
\[
f(2) = 16 - 24 + 14 - 1
\]
Calculating step by step:
\[
f(2) = 16 - 24 = -8
\]
\[
-8 + 14 = 6
\]
\[
6 - 1 = 5
\]
Thus, the remainder when \( f(x) \) is divided by \( (x - 2) \) is \( \boxed{5} \).
In this case, we need to evaluate \( f(2) \):
\[
f(2) = (2)^4 - 3(2)^3 + 7(2) - 1
\]
Calculating each term:
1. \( (2)^4 = 16 \)
2. \( -3(2)^3 = -3(8) = -24 \)
3. \( 7(2) = 14 \)
4. The final term is \( -1 \)
Now substituting back into the equation:
\[
f(2) = 16 - 24 + 14 - 1
\]
Calculating step by step:
\[
f(2) = 16 - 24 = -8
\]
\[
-8 + 14 = 6
\]
\[
6 - 1 = 5
\]
Thus, the remainder when \( f(x) \) is divided by \( (x - 2) \) is \( \boxed{5} \).
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