Question
Select the equivalent expression.
\[\left(\dfrac{a^{-3}}{b^{2}}\right)^{4}=?\]
Choose 1 answer:
Choose 1 answer:
(Choice A)
\[\dfrac{b^2}{a^7}\]
A
\[\dfrac{b^2}{a^7}\]
(Choice B)
\[\dfrac{1}{a^{12}\cdot b^{8}}\]
B
\[\dfrac{1}{a^{12}\cdot b^{8}}\]
(Choice C)
\[\left( \dfrac{b}{a}\right)^{20}\]
C
\[\left( \dfrac{b}{a}\right)^{20}\]
\[\left(\dfrac{a^{-3}}{b^{2}}\right)^{4}=?\]
Choose 1 answer:
Choose 1 answer:
(Choice A)
\[\dfrac{b^2}{a^7}\]
A
\[\dfrac{b^2}{a^7}\]
(Choice B)
\[\dfrac{1}{a^{12}\cdot b^{8}}\]
B
\[\dfrac{1}{a^{12}\cdot b^{8}}\]
(Choice C)
\[\left( \dfrac{b}{a}\right)^{20}\]
C
\[\left( \dfrac{b}{a}\right)^{20}\]
Answers
GPT-4o mini
To simplify the expression \(\left(\dfrac{a^{-3}}{b^{2}}\right)^{4}\), we can use the property of exponents \((\frac{x}{y})^n = \frac{x^n}{y^n}\).
1. Start by applying the exponent to both the numerator and the denominator:
\[
\left(\dfrac{a^{-3}}{b^{2}}\right)^{4} = \dfrac{(a^{-3})^{4}}{(b^{2})^{4}}
\]
2. Now calculate the exponents:
\[
(a^{-3})^{4} = a^{-12}
\]
\[
(b^{2})^{4} = b^{8}
\]
3. Substitute these back into the fraction:
\[
\dfrac{(a^{-3})^{4}}{(b^{2})^{4}} = \dfrac{a^{-12}}{b^{8}}
\]
4. Since \(a^{-12} = \frac{1}{a^{12}}\), we can rewrite this as:
\[
\dfrac{a^{-12}}{b^{8}} = \dfrac{1}{a^{12} \cdot b^{8}}
\]
So the equivalent expression is:
\[
\dfrac{1}{a^{12} \cdot b^{8}}
\]
The correct choice is:
(Choice B) \(\dfrac{1}{a^{12}\cdot b^{8}}\)
1. Start by applying the exponent to both the numerator and the denominator:
\[
\left(\dfrac{a^{-3}}{b^{2}}\right)^{4} = \dfrac{(a^{-3})^{4}}{(b^{2})^{4}}
\]
2. Now calculate the exponents:
\[
(a^{-3})^{4} = a^{-12}
\]
\[
(b^{2})^{4} = b^{8}
\]
3. Substitute these back into the fraction:
\[
\dfrac{(a^{-3})^{4}}{(b^{2})^{4}} = \dfrac{a^{-12}}{b^{8}}
\]
4. Since \(a^{-12} = \frac{1}{a^{12}}\), we can rewrite this as:
\[
\dfrac{a^{-12}}{b^{8}} = \dfrac{1}{a^{12} \cdot b^{8}}
\]
So the equivalent expression is:
\[
\dfrac{1}{a^{12} \cdot b^{8}}
\]
The correct choice is:
(Choice B) \(\dfrac{1}{a^{12}\cdot b^{8}}\)