Asked by johnica martin
these are some problems i do not get any help is appreciated. These are copied exactly from the worksheet so i don't think i wrote anything wrong. Please explain it for me and could i get the answer thanks (:
Log7 x= ½ log7 36 (log base 7)
log x=2log 5+ log 4
Logx 10 + logx 8-logx 5= 4 (log base x)
5^2x=3
Log7 x= ½ log7 36 (log base 7)
log x=2log 5+ log 4
Logx 10 + logx 8-logx 5= 4 (log base x)
5^2x=3
Answers
Answered by
Damon
Log7 x= ½ log7 36 (log base 7)
log7 (x) = log7 (36)^.5
so
x = 36^.5 = 6
log7 (x) = log7 (36)^.5
so
x = 36^.5 = 6
Answered by
Damon
log x=2log 5+ log 4
log x = log(5)^2 + log 4
log x = log (25*4)
x = 100
log x = log(5)^2 + log 4
log x = log (25*4)
x = 100
Answered by
Damon
Logx 10 + logx 8-logx 5= 4 (log base x)
logx (10*8/5) = 4
logx (16) = 4
16 = x^4
well, what to the fourth power = 16 ?
logx (10*8/5) = 4
logx (16) = 4
16 = x^4
well, what to the fourth power = 16 ?
Answered by
Damon
5^2x=3
2 x log 5 = log 3
x log 25 = log 3
x = log 3 / log 25
2 x log 5 = log 3
x log 25 = log 3
x = log 3 / log 25
Answered by
johnica martin
i have this problem ½ log2 x=3log22-log24
(log base 2) it is kinda of the same as the first one but i don't undersand how you got them?
(log base 2) it is kinda of the same as the first one but i don't undersand how you got them?
Answered by
Damon
log2 (x^.5 ) = log2 (8) - log2(4)
log2 (x^.5) = log2 (2) which is 1
log 2 (x^.5) = 1
x^.5 = 2^1 = 2
x = 2^2 = 4
log2 (x^.5) = log2 (2) which is 1
log 2 (x^.5) = 1
x^.5 = 2^1 = 2
x = 2^2 = 4
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