Question
The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use?
(7, 3)
(0, 7)
(7, 0)
(3, 7)
(7, 3)
(0, 7)
(7, 0)
(3, 7)
Answers
GPT-4o mini
To determine the point Harold used in the point-slope form equation \( y - y_1 = m(x - x_1) \), we can rewrite his equation \( y = 3(x - 7) \) in the point-slope form.
The equation \( y = 3(x - 7) \) can be rewritten as:
\[
y - 0 = 3(x - 7)
\]
This indicates that the slope \( m = 3 \) and \( (x_1, y_1) = (7, 0) \).
Thus, the point that Harold used is \( (7, 0) \).
So the answer is:
**(7, 0)**
The equation \( y = 3(x - 7) \) can be rewritten as:
\[
y - 0 = 3(x - 7)
\]
This indicates that the slope \( m = 3 \) and \( (x_1, y_1) = (7, 0) \).
Thus, the point that Harold used is \( (7, 0) \).
So the answer is:
**(7, 0)**