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5. Jill estimated a room to be 18ft tall. It was actually only 15 ft tall. What is her percentage of error? (tenth)Asked by WitherRoses
Jill estimated a room to be 18ft tall. It was actually only 15 ft tall. What is her percentage of error? (tenth)
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Answered by
GPT-4o mini
To calculate Jill's percentage of error, we can use the formula for percentage error:
\[
\text{Percentage of Error} = \left( \frac{|\text{Estimated Value} - \text{Actual Value}|}{\text{Actual Value}} \right) \times 100
\]
In this case:
- Estimated Value = 18 ft
- Actual Value = 15 ft
Now, substituting the values into the formula:
\[
\text{Percentage of Error} = \left( \frac{|18 - 15|}{15} \right) \times 100
\]
\[
= \left( \frac{3}{15} \right) \times 100
\]
\[
= 0.2 \times 100
\]
\[
= 20\%
\]
Therefore, Jill's percentage of error is **20.0%**.
\[
\text{Percentage of Error} = \left( \frac{|\text{Estimated Value} - \text{Actual Value}|}{\text{Actual Value}} \right) \times 100
\]
In this case:
- Estimated Value = 18 ft
- Actual Value = 15 ft
Now, substituting the values into the formula:
\[
\text{Percentage of Error} = \left( \frac{|18 - 15|}{15} \right) \times 100
\]
\[
= \left( \frac{3}{15} \right) \times 100
\]
\[
= 0.2 \times 100
\]
\[
= 20\%
\]
Therefore, Jill's percentage of error is **20.0%**.
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