To reflect the function \( f(x) = (x+1)^2 \) horizontally, we will replace \( x \) with \( -x \). Thus, the reflected function is:
\[ f(-x) = (-x + 1)^2 = (1 - x)^2. \]
Now let's analyze the behavior of both functions and determine the position of the point \( (-4, 9) \) in the reflected function.
- Original Function: Let's calculate \( f(-4) \):
\[ f(-4) = (-4 + 1)^2 = (-3)^2 = 9. \]
So, the point \( (-4, 9) \) is on the original function \( f(x) \).
- Reflected Function: Now, we want to find the equivalent point in the reflected function \( f(-x) \). The point \( (-4, 9) \) reflects to the point \( (4, 9) \) in the equation \( f(-x) \).
Thus, the position of the point \( (-4, 9) \) in the reflected function \( f(-x) \) is:
\[ (4, 9). \]
In conclusion, the point \( (-4, 9) \) reflects to \( (4, 9) \) in \( f(-x) \).