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Original Question
22 students completed 80 puzzles how many puzzles would 1 student complet round to tenthAsked by WitherRoses
22 students completed 80 puzzles. How many puzzles would 1 student complete? (round to tenth)
Answers
Answered by
WitherRoses
step by step 80 / 20
Answered by
GPT-4o mini
To find out how many puzzles one student would complete, you can divide the total number of puzzles by the number of students:
\[
\text{Puzzles per student} = \frac{\text{Total puzzles}}{\text{Number of students}} = \frac{80}{22}
\]
Calculating that gives:
\[
\frac{80}{22} \approx 3.636363636
\]
Rounding to the tenth, one student would complete approximately:
\[
\text{Puzzles per student} \approx 3.6
\]
So, one student would complete about **3.6 puzzles**.
\[
\text{Puzzles per student} = \frac{\text{Total puzzles}}{\text{Number of students}} = \frac{80}{22}
\]
Calculating that gives:
\[
\frac{80}{22} \approx 3.636363636
\]
Rounding to the tenth, one student would complete approximately:
\[
\text{Puzzles per student} \approx 3.6
\]
So, one student would complete about **3.6 puzzles**.
Answered by
GPT-4o mini
Sure! Let's go step by step to divide \( 80 \) by \( 22 \).
1. **Set Up the Division**:
We want to divide \( 80 \) by \( 22 \). This can be expressed as:
\[
80 \div 22
\]
2. **Perform the Division**:
Start by seeing how many times \( 22 \) can fit into \( 80 \).
- **Estimate**:
- \( 22 \times 1 = 22 \)
- \( 22 \times 2 = 44 \)
- \( 22 \times 3 = 66 \)
- \( 22 \times 4 = 88 \) (too much)
So, \( 22 \) can fit into \( 80 \) three times.
3. **Multiply**:
Now we multiply \( 22 \) by \( 3 \):
\[
22 \times 3 = 66
\]
4. **Subtract**:
Now subtract \( 66 \) from \( 80 \):
\[
80 - 66 = 14
\]
5. **Write the Remainder**:
Now we have a remainder of \( 14 \).
6. **Add a Decimal**:
Since \( 80 \) is greater than \( 22 \), we can continue dividing by adding a decimal point and a zero to the \( 14 \) to make it \( 140 \):
\[
80.0 \div 22 = 3.0
\]
7. **Continue Division**:
Now determine how many times \( 22 \) fits into \( 140 \):
- \( 22 \times 6 = 132 \)
- \( 22 \times 7 = 154 \) (too much)
So, \( 22 \) fits \( 6 \) times.
8. **Multiply Again**:
Multiply \( 22 \) by \( 6 \):
\[
22 \times 6 = 132
\]
9. **Subtract Again**:
Now subtract \( 132 \) from \( 140 \):
\[
140 - 132 = 8
\]
10. **Add Another Decimal**:
Add to the division result:
\[
80.00 \div 22 \approx 3.6
\]
11. **Repeat for More Precision**:
Add another \( 0 \) to \( 8 \) to make \( 80 \) and continue dividing:
- \( 22 \) fits \( 3 \) times into \( 80 \) (because \( 22 \times 3 = 66 \)).
- Subtract \( 66 \) from \( 80 \):
\[
80 - 66 = 14
\]
12. **Final Result**:
The result we derived from dividing \( 80 \) by \( 22 \) gives us:
\[
80 \div 22 \approx 3.636363636...
\]
When rounded to the nearest tenth, it is \( 3.6 \).
So, the final answer is that one student would complete approximately **3.6 puzzles**.
1. **Set Up the Division**:
We want to divide \( 80 \) by \( 22 \). This can be expressed as:
\[
80 \div 22
\]
2. **Perform the Division**:
Start by seeing how many times \( 22 \) can fit into \( 80 \).
- **Estimate**:
- \( 22 \times 1 = 22 \)
- \( 22 \times 2 = 44 \)
- \( 22 \times 3 = 66 \)
- \( 22 \times 4 = 88 \) (too much)
So, \( 22 \) can fit into \( 80 \) three times.
3. **Multiply**:
Now we multiply \( 22 \) by \( 3 \):
\[
22 \times 3 = 66
\]
4. **Subtract**:
Now subtract \( 66 \) from \( 80 \):
\[
80 - 66 = 14
\]
5. **Write the Remainder**:
Now we have a remainder of \( 14 \).
6. **Add a Decimal**:
Since \( 80 \) is greater than \( 22 \), we can continue dividing by adding a decimal point and a zero to the \( 14 \) to make it \( 140 \):
\[
80.0 \div 22 = 3.0
\]
7. **Continue Division**:
Now determine how many times \( 22 \) fits into \( 140 \):
- \( 22 \times 6 = 132 \)
- \( 22 \times 7 = 154 \) (too much)
So, \( 22 \) fits \( 6 \) times.
8. **Multiply Again**:
Multiply \( 22 \) by \( 6 \):
\[
22 \times 6 = 132
\]
9. **Subtract Again**:
Now subtract \( 132 \) from \( 140 \):
\[
140 - 132 = 8
\]
10. **Add Another Decimal**:
Add to the division result:
\[
80.00 \div 22 \approx 3.6
\]
11. **Repeat for More Precision**:
Add another \( 0 \) to \( 8 \) to make \( 80 \) and continue dividing:
- \( 22 \) fits \( 3 \) times into \( 80 \) (because \( 22 \times 3 = 66 \)).
- Subtract \( 66 \) from \( 80 \):
\[
80 - 66 = 14
\]
12. **Final Result**:
The result we derived from dividing \( 80 \) by \( 22 \) gives us:
\[
80 \div 22 \approx 3.636363636...
\]
When rounded to the nearest tenth, it is \( 3.6 \).
So, the final answer is that one student would complete approximately **3.6 puzzles**.