To determine the chances of having offspring with short tails from a long-tailed mouse that is heterozygous (let's denote the alleles as L for long tail and l for short tail) and a short-tailed mouse (which must be homozygous recessive, ll), we can set up a simple Punnett square.
The genotypes are as follows:
- Heterozygous long-tailed mouse: Ll
- Short-tailed mouse: ll
The possible allele combinations from these parents are:
-
From the heterozygous parent (Ll):
- L (dominant for long tail)
- l (recessive for short tail)
-
From the homozygous recessive parent (ll):
Now, filling out the Punnett square:
l | l
-----------------
L | Ll | Ll | (long tail)
-----------------
l | ll | ll | (short tail)
From this, we can see that there are:
- 2 Ll (long-tailed)
- 2 ll (short-tailed)
Thus, the ratio of offspring is 2 long-tailed (Ll) to 2 short-tailed (ll), which can be simplified to 1:1.
Therefore, the chances of having offspring with short tails (ll) are 50%.