Use the image to answer the question.

A straight, solid line connects plotted points E and F on a coordinate plane. The line slopes downward from left to right. Point E is left parenthesis negative 6 comma 1 right parenthesis. Point F is left parenthesis 2 comma negative 5 right parenthesis.

How would you set up the distance formula to find the distance between points E and F.

(1 point)
Responses

d=((−2)+6)2+(5+1)2−−−−−−−−−−−−−−−−−−√
d is equal to square root of open paren negative 2 plus 6 close paren squared plus open paren 5 plus 1 close paren squared end root

d=(6−2)2+(1−5)2−−−−−−−−−−−−−−−√
d is equal to square root of open paren 6 minus 2 close paren squared plus open paren 1 minus 5 close paren squared end root

d=(2−6)2+(5−1)2−−−−−−−−−−−−−−−√
d is equal to square root of open paren 2 minus 6 close paren squared plus open paren 5 minus 1 close paren squared end root

d=(−6−2)2+(1−(−5))2−−−−−−−−−−−−−−−−−−−√
d is equal to square root of open paren negative 6 minus 2 close paren squared plus open paren 1 minus negative 5 close paren squared end root

1 answer

To find the distance between the points E (6,1) and F (2,5) using the distance formula, we use the following formula:

d=(x2x1)2+(y2y1)2

Where (x1,y1) are the coordinates of point E and (x2,y2) are the coordinates of point F. Substituting in the specific coordinates:

  • x1=6, y1=1
  • x2=2, y2=5

The distance formula setup would be:

d=(2(6))2+(51)2

This simplifies to:

d=(2+6)2+(51)2 d=(8)2+(6)2

None of the provided responses are exactly correct because they contain errors in the setup. However, the closest response, employing the correct adjustments, would be:

d = square root of open paren 2 minus negative 6 close paren squared plus open paren negative 5 minus 1 close paren squared end root

Since the intended expression and calculations involve:

  • x2x1=2(6)=2+6=8
  • y2y1=51=6

To sum it all up, the official option setup was not available, but the closely matching answer with positioning correction should be indicated.