Given the information about triangles \( \triangle ABD \) and \( \triangle ECD \) being similar, we can set up a proportion based on the corresponding sides of the triangles.
First, we identify the dimensions and relationships:
- \( AD = 32 \) feet
- \( AE = 8 \) feet
- The height of the cell phone tower from point \( D \) is \( 114 \) feet.
- The height of the drone above the ground at point \( C \) is \( h \) feet.
Since \( AE \) is a segment along \( AD \), we have:
\[ DE = AD - AE = 32 - 8 = 24 \text{ feet} \]
Given that angles \( DAB \) and \( DEC \) are right angles, we can use the fact that the triangles are similar due to the congruence of angles \( B \) and \( C \).
From \( \triangle ABD \) to \( \triangle ECD \), we can write the proportion based on the corresponding heights and bases:
\[ \frac{\text{height of tower (114 feet)}}{AD (32 \text{ feet})} = \frac{h}{CE} \]
We need \( CE \), which is the horizontal distance from point \( C \) to point \( E \).
From the similar triangles, we know the horizontal proportion by \( AD \) and also the fact that \( AE = 8 \) feet and \( DE = 24 \) feet.
Since \( C \) is at the same level vertically as \( D \) because of the right angles given; therefore, we can directly use the ratio of corresponding sides:
\[ \frac{114}{32} = \frac{h}{24} \]
Now, we proceed with the ratio:
Cross-multiplying to resolve gives us:
\[ 114 \cdot 24 = h \cdot 32 \]
Calculating \( 114 \cdot 24 = 2736 \):
Thus,
\[ 2736 = 32h \]
Now, solve for \( h \):
\[ h = \frac{2736}{32} = 85.5 \]
Therefore, the height \( h \) of the drone is
\[ \boxed{85.5} \text{ feet}. \]