Question
Use the image to answer the question.
A coordinate graph goes from negative 10 to 10 in 1-unit increments on both the x- and y-axes. Two linear equations are graphed, along with two points.
The image shows the graph of the system of linear equations {y=2x+2y=2x−4
. Which of the following points, if any, are solutions to the system of equations?
(1 point)
Responses
(0,−4)
open paren 0 comma negative 4 close paren
Both of these points are solutions.
Both of these points are solutions.
(0,2)
open paren 0 comma 2 close paren
Neither of these points are solutions.
A coordinate graph goes from negative 10 to 10 in 1-unit increments on both the x- and y-axes. Two linear equations are graphed, along with two points.
The image shows the graph of the system of linear equations {y=2x+2y=2x−4
. Which of the following points, if any, are solutions to the system of equations?
(1 point)
Responses
(0,−4)
open paren 0 comma negative 4 close paren
Both of these points are solutions.
Both of these points are solutions.
(0,2)
open paren 0 comma 2 close paren
Neither of these points are solutions.
Answers
GPT-4o mini
To determine whether the given points are solutions to the system of equations \( y = 2x + 2 \) and \( y = 2x - 4 \), we can substitute the x-coordinates of each point into both equations.
1. For the point \( (0, -4) \):
- Substitute \( x = 0 \) into the first equation:
\[
y = 2(0) + 2 = 2
\]
This does not equal \(-4\), so \( (0, -4) \) is not a solution to the first equation.
- Substitute \( x = 0 \) into the second equation:
\[
y = 2(0) - 4 = -4
\]
This matches the y-coordinate \(-4\), so \( (0, -4) \) is a solution to the second equation.
2. For the point \( (0, 2) \):
- Substitute \( x = 0 \) into the first equation:
\[
y = 2(0) + 2 = 2
\]
This matches the y-coordinate \(2\), so \( (0, 2) \) is a solution to the first equation.
- Substitute \( x = 0 \) into the second equation:
\[
y = 2(0) - 4 = -4
\]
This does not equal \(2\), so \( (0, 2) \) is not a solution to the second equation.
Summary:
- The point \( (0, -4) \) is a solution to only the second equation.
- The point \( (0, 2) \) is a solution to only the first equation.
Therefore, the correct response is: **Neither of these points are solutions.**
1. For the point \( (0, -4) \):
- Substitute \( x = 0 \) into the first equation:
\[
y = 2(0) + 2 = 2
\]
This does not equal \(-4\), so \( (0, -4) \) is not a solution to the first equation.
- Substitute \( x = 0 \) into the second equation:
\[
y = 2(0) - 4 = -4
\]
This matches the y-coordinate \(-4\), so \( (0, -4) \) is a solution to the second equation.
2. For the point \( (0, 2) \):
- Substitute \( x = 0 \) into the first equation:
\[
y = 2(0) + 2 = 2
\]
This matches the y-coordinate \(2\), so \( (0, 2) \) is a solution to the first equation.
- Substitute \( x = 0 \) into the second equation:
\[
y = 2(0) - 4 = -4
\]
This does not equal \(2\), so \( (0, 2) \) is not a solution to the second equation.
Summary:
- The point \( (0, -4) \) is a solution to only the second equation.
- The point \( (0, 2) \) is a solution to only the first equation.
Therefore, the correct response is: **Neither of these points are solutions.**