A 60.0 kg person bends his knees and then jumps straight up. After his feet leave the floor, his motion is unaffected by air resistance and his center of mass rises by a maximum of 14.9 cm. Model the floor as completely solid and motionless.

a)With what momentum does the person leave the floor? kg-m/s up
v=(2x9.8x14.9)^(1/2)
p=60v

b)With what kinetic energy does the person leave the floor?
k=1/2(60)v^2

1 answer

Your method is fine except the height H must be converted to meters. Also: why don't you compute v and provide numerical answers, with units (kg m/s and Joules)?
v = 1.7 m/s