Question
The velocity ratio of 6 and an efficiency of 75% calculate the effort needed to raise a load of 120N
Answers
GPT-4o mini
To calculate the effort needed to raise a load when given the velocity ratio (VR) and efficiency (%), we can use the following formula:
\[
\text{Effort} = \frac{\text{Load}}{\text{Efficiency} \times \text{Velocity Ratio}}
\]
Where:
- Load = 120 N
- Efficiency = 75% = 0.75 (in decimal form)
- Velocity Ratio (VR) = 6
Now, substituting the values into the formula:
\[
\text{Effort} = \frac{120 \, \text{N}}{0.75 \times 6}
\]
Calculating the denominator:
\[
0.75 \times 6 = 4.5
\]
Now substitute this back into the formula:
\[
\text{Effort} = \frac{120 \, \text{N}}{4.5}
\]
Calculating the effort:
\[
\text{Effort} = 26.67 \, \text{N} \quad (\text{approximately})
\]
Thus, the effort needed to raise a load of 120 N is approximately **26.67 N**.
\[
\text{Effort} = \frac{\text{Load}}{\text{Efficiency} \times \text{Velocity Ratio}}
\]
Where:
- Load = 120 N
- Efficiency = 75% = 0.75 (in decimal form)
- Velocity Ratio (VR) = 6
Now, substituting the values into the formula:
\[
\text{Effort} = \frac{120 \, \text{N}}{0.75 \times 6}
\]
Calculating the denominator:
\[
0.75 \times 6 = 4.5
\]
Now substitute this back into the formula:
\[
\text{Effort} = \frac{120 \, \text{N}}{4.5}
\]
Calculating the effort:
\[
\text{Effort} = 26.67 \, \text{N} \quad (\text{approximately})
\]
Thus, the effort needed to raise a load of 120 N is approximately **26.67 N**.