Question

A class of 195 students went on a field trip. They took 19 Vehicles, some cars, some buses .If each can holds 5 students and each bus holds 25 students, how many buses did they take?

Answer 1

Let \( c \) represent the number of cars and \( b \) represent the number of buses. We know from the problem that:

1. The total number of vehicles is 19:
\[
c + b = 19
\]
2. Each car holds 5 students and each bus holds 25 students. The total number of students transported is 195:
\[
5c + 25b = 195
\]

Now, we can solve these equations step by step.

First, let's simplify the second equation by dividing everything by 5:
\[
c + 5b = 39
\]

We now have the system of equations:
1. \( c + b = 19 \) (1)
2. \( c + 5b = 39 \) (2)

Next, we can use equation (1) to express \( c \) in terms of \( b \):
\[
c = 19 - b
\]

Now substitute this expression for \( c \) into equation (2):
\[
(19 - b) + 5b = 39
\]
This simplifies to:
\[
19 + 4b = 39
\]
Subtract 19 from both sides:
\[
4b = 20
\]
Now divide by 4:
\[
b = 5
\]

Now that we have \( b \), we can find \( c \):
\[
c = 19 - b = 19 - 5 = 14
\]

Thus, the class took **5 buses**.