To find the slope (m) of the line passing through the points \((0, 9)\) and \((3, 0)\), we can use the slope formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Here, \((x_1, y_1) = (0, 9)\) and \((x_2, y_2) = (3, 0)\). Plugging in these values:
\[ m = \frac{0 - 9}{3 - 0} = \frac{-9}{3} = -3 \]
Next, we can use the point-slope form of the line equation, which is \(y - y_1 = m(x - x_1)\). Using the point \((0, 9)\):
\[ y - 9 = -3(x - 0) \]
Simplifying this, we get:
\[ y - 9 = -3x \] \[ y = -3x + 9 \]
Thus, the slope is \(-3\) and the equation of the line is \(y = -3x + 9\).
So the correct answer is: m = StartFraction 9 minus 0 Over 0 minus 3 EndFraction; y = –3x + 9.