Charlie wants to order lunch for his friends. He'll order 6 sandwiches and a $3 kid's meal for his little brother. Charlie has $27. How much can he spend on each sandwich if they are all the same price?

Question

Charlie wants to order lunch for his friends. He'll order 6 sandwiches and a $3 kid's meal for his little brother. Charlie has $27. How much can he spend on each sandwich if they are all the same price?
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Groups
The inequality representing how much Charlie can spend is
Charlie can spend
choose your answer...
choose your answer...

GPT-4o mini · Answer

To determine how much Charlie can spend on each sandwich, we first need to set up the relationship between his budget and his purchases. Charlie has a total budget of $27.

He is going to buy 6 sandwiches and 1 kid's meal for $3.

Subtract the cost of the kid's meal from his total budget:
Total budget = $27
Cost of kid's meal = $3
Remaining budget for sandwiches = $27 - $3 = $24
Let $x$ be the price of each sandwich.
Since Charlie is buying 6 sandwiches, the total cost for the sandwiches can be expressed as $6 x$ .
Set up the inequality:
The total cost of the sandwiches must be less than or equal to his remaining budget: $6 x \leq 24$
Solve for $x$ : To find out how much he can spend on each sandwich, divide both sides of the inequality by 6: $x \leq \frac{24}{6}$ $x \leq 4$

Therefore, Charlie can spend $4 or less on each sandwich.

In summary, the inequality representing how much Charlie can spend is: $6 x \leq 24$ which means Charlie can spend $4 or less on each sandwich.

Answer

The inequality representing how much Charlie can spend is Previous choose your answer... ^ choose your answer... 6x+ 3≤27 6x+3≥27 3x+6≥27 3x+6<27

GPT-4o mini · Answer

The correct inequality representing how much Charlie can spend is:

$6 x + 3 \leq 27$

Here's the breakdown:

$6 x$ : represents the total cost of the 6 sandwiches, where $x$ is the price of each sandwich.
$3$ : represents the cost of the kid's meal.
$27$ : is Charlie's total budget.

So, the inequality $6 x + 3 \leq 27$ captures the relationship correctly, indicating that the total cost of the sandwiches plus the kid's meal should not exceed Charlie's budget.

Therefore, the first option $6 x + 3 \leq 27$ is the correct choice.