Question
Use the table to answer the question.
x Substituted Evaluate True Statement?
7−11−−√
7
11−7–√
7+11−−√
11+7–√
For the quadratic equation (x−7)2=11
, complete the table by testing each of the given values to determine whether it is a solution. Identify the two solutions to the quadratic equation.
(1 point)
The smaller of the two solutions is x=
. The larger of the two solutions is x=
.
Remaining Attempts : 3
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x Substituted Evaluate True Statement?
7−11−−√
7
11−7–√
7+11−−√
11+7–√
For the quadratic equation (x−7)2=11
, complete the table by testing each of the given values to determine whether it is a solution. Identify the two solutions to the quadratic equation.
(1 point)
The smaller of the two solutions is x=
. The larger of the two solutions is x=
.
Remaining Attempts : 3
Skip to navigation
page 15 of 16
Answers
GPT-4o mini
To solve the quadratic equation \((x - 7)^2 = 11\), we'll first find the solutions by taking the square root of both sides.
1. Start by rewriting the equation:
\[(x - 7)^2 = 11\]
2. Take the square root of both sides:
\[x - 7 = \pm \sqrt{11}\]
This leads to two equations:
\[x - 7 = \sqrt{11}\]
\[x - 7 = -\sqrt{11}\]
3. Solve for \(x\) in each case:
- For \(x - 7 = \sqrt{11}\):
\[x = 7 + \sqrt{11}\]
- For \(x - 7 = -\sqrt{11}\):
\[x = 7 - \sqrt{11}\]
Now we have the two solutions:
- The smaller solution is \(x = 7 - \sqrt{11}\)
- The larger solution is \(x = 7 + \sqrt{11}\)
We can approximate \(\sqrt{11}\):
\(\sqrt{11} \approx 3.3166\)
Thus:
- The smaller solution:
\[x \approx 7 - 3.3166 \approx 3.6834\]
- The larger solution:
\[x \approx 7 + 3.3166 \approx 10.3166\]
However, for exact values:
- The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x = 7 + \sqrt{11}\).
**Final Answer:**
The smaller of the two solutions is \(x = 7 - \sqrt{11}\). The larger of the two solutions is \(x = 7 + \sqrt{11}\).
1. Start by rewriting the equation:
\[(x - 7)^2 = 11\]
2. Take the square root of both sides:
\[x - 7 = \pm \sqrt{11}\]
This leads to two equations:
\[x - 7 = \sqrt{11}\]
\[x - 7 = -\sqrt{11}\]
3. Solve for \(x\) in each case:
- For \(x - 7 = \sqrt{11}\):
\[x = 7 + \sqrt{11}\]
- For \(x - 7 = -\sqrt{11}\):
\[x = 7 - \sqrt{11}\]
Now we have the two solutions:
- The smaller solution is \(x = 7 - \sqrt{11}\)
- The larger solution is \(x = 7 + \sqrt{11}\)
We can approximate \(\sqrt{11}\):
\(\sqrt{11} \approx 3.3166\)
Thus:
- The smaller solution:
\[x \approx 7 - 3.3166 \approx 3.6834\]
- The larger solution:
\[x \approx 7 + 3.3166 \approx 10.3166\]
However, for exact values:
- The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x = 7 + \sqrt{11}\).
**Final Answer:**
The smaller of the two solutions is \(x = 7 - \sqrt{11}\). The larger of the two solutions is \(x = 7 + \sqrt{11}\).