Question
he density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = )
.25 cm3
.67 cm3
1.48 cm3
2.50 cm3
.25 cm3
.67 cm3
1.48 cm3
2.50 cm3
Answers
GPT-4o mini
To find the volume of the gold nugget, we can use the formula relating density (\(D\)), mass (\(m\)), and volume (\(V\)):
\[
D = \frac{m}{V}
\]
We can rearrange this formula to solve for volume (\(V\)):
\[
V = \frac{m}{D}
\]
In this case, the mass \(m\) of the gold nugget is given as 13 g, and the density \(D\) of gold is 19.3 g/cm³. Plugging in these values:
\[
V = \frac{13 \, \text{g}}{19.3 \, \text{g/cm}^3}
\]
Calculating this gives:
\[
V \approx 0.6746 \, \text{cm}^3
\]
Rounding to two decimal places, we have:
\[
V \approx 0.67 \, \text{cm}^3
\]
Therefore, the volume of the 13 g gold nugget is approximately \(0.67 \, \text{cm}^3\).
The correct answer is **0.67 cm³**.
\[
D = \frac{m}{V}
\]
We can rearrange this formula to solve for volume (\(V\)):
\[
V = \frac{m}{D}
\]
In this case, the mass \(m\) of the gold nugget is given as 13 g, and the density \(D\) of gold is 19.3 g/cm³. Plugging in these values:
\[
V = \frac{13 \, \text{g}}{19.3 \, \text{g/cm}^3}
\]
Calculating this gives:
\[
V \approx 0.6746 \, \text{cm}^3
\]
Rounding to two decimal places, we have:
\[
V \approx 0.67 \, \text{cm}^3
\]
Therefore, the volume of the 13 g gold nugget is approximately \(0.67 \, \text{cm}^3\).
The correct answer is **0.67 cm³**.