Asked by Danessa
One model train travels around a loop every 5 minutes. The other travels on anothe loop every 4 minutes. If they begin at the same point at the same time, how much time will pass before they meet at that point again?
Answers
Answered by
bobpursley
The rate for the first is one loop per 5min, the other one loop per four minutes. The combined rate is the sum of these:
1loop= (lloop/5min + 1loop/4min)*time
time= 1/(1/5 + 1/4) minutes
This is somewhat tricky to get combined, if you wish, you can make decimas..
time= 1/(.2+.25)= 1/.45 and you take it from there.
1loop= (lloop/5min + 1loop/4min)*time
time= 1/(1/5 + 1/4) minutes
This is somewhat tricky to get combined, if you wish, you can make decimas..
time= 1/(.2+.25)= 1/.45 and you take it from there.
Answered by
Cata
200,000=?thousands ? ten thousands ? hundred thousands
Answered by
bobpursley
time= 1/.45= 2.2 seconds.
Answered by
bobpursley
oops..time= 2.2 minutes.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.