Let's define variables for the prices of the melons:
- Let \( h \) be the cost per pound of honeydew melon.
- Let \( w \) be the cost per pound of watermelon.
We can set up a system of equations based on the information provided:
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From the first scenario: \[ 7h + 6w = 39 \]
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From the second scenario: \[ 4h + 6w = 30 \]
Now we have the system of equations:
\[ \begin{align*} (1) & \quad 7h + 6w = 39 \ (2) & \quad 4h + 6w = 30 \end{align*} \]
We can eliminate \( w \) by subtracting equation (2) from equation (1): \[ (7h + 6w) - (4h + 6w) = 39 - 30 \] This simplifies to: \[ 3h = 9 \] Dividing both sides by 3 gives us: \[ h = 3 \]
Next, we substitute \( h = 3 \) into one of the original equations to find \( w \). We'll use equation (2): \[ 4(3) + 6w = 30 \] This simplifies to: \[ 12 + 6w = 30 \] Subtracting 12 from both sides: \[ 6w = 18 \] Dividing both sides by 6 gives us: \[ w = 3 \]
Now we have the costs:
- Honeydew melon costs \( h = 3 \) dollars per pound.
- Watermelon costs \( w = 3 \) dollars per pound.
Therefore, we can fill in the blanks: Honeydew melon costs $ 3 per pound and watermelon costs $ 3 per pound.