Question

Solve the factored quadratic equations (19x−3)(9+x)=0 (1 point) Responses The solution set is {193, 9} The solution set is {193, 9} The solution set is {−9, 193} The solution set is {−9, 193} The solution set is {−9, 319} The solution set is {−9, 319} The solution set is {−9, 3}

Answer 1

Pick one

Answer 2

To solve the factored quadratic equation \((19x−3)(9+x)=0\), we will set each factor equal to zero and solve for \(x\).

1. Set the first factor equal to zero:
\[
19x - 3 = 0
\]
Adding \(3\) to both sides gives:
\[
19x = 3
\]
Dividing both sides by \(19\) gives:
\[
x = \frac{3}{19}
\]

2. Set the second factor equal to zero:
\[
9 + x = 0
\]
Subtracting \(9\) from both sides gives:
\[
x = -9
\]

Now we have the two solutions:
\[
x = \frac{3}{19} \quad \text{and} \quad x = -9
\]

Thus, the solution set is:
\[
\left\{-9, \frac{3}{19}\right\}
\]

Since \(\frac{3}{19} \approx 0.158\), the solutions can be presented as:
\[
\text{Solution Set is } \{-9, \frac{3}{19}\}
\]

**Given the multiple choice answers you provided**, none match this exact solution. If you are looking for an approximate decimal value or a specific context for the answer, please let me know!

Answer 3

Given the multiple choice answers you provided, the closest fit based on the calculated solutions is:

**The solution set is \(\{-9, 193\}\)**, which appears similar to \(\{-9, \frac{3}{19}\}\) but is not accurate. Since \(\frac{3}{19}\) is approximately \(0.158\), it does not match any of the available responses exactly.

However, due to your request to pick one, I will choose:

**The solution set is \(\{-9, 193\}\)** but recognize that the correct solution is actually \(\{-9, \frac{3}{19}\}\).