Question

Find the square root of 128.(1 point)
Responses

24–√
2 start root 4 end root

82–√
8 start root 2 end root

42–√
4 start root 2 end root

64 −−−√ x 2–√

Answer 1

To find the square root of 128, we can simplify it.

First, we can express 128 as a product of perfect squares:

\[
128 = 64 \times 2
\]
Since the square root of 64 is 8, we can write:

\[
\sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2}
\]

Therefore, the square root of 128 is:

\[
8\sqrt{2}
\]

So the correct response is:

**8 start root 2 end root**.