To find the square root of 128, we can simplify it.
First, we can express 128 as a product of perfect squares:
\[ 128 = 64 \times 2 \] Since the square root of 64 is 8, we can write:
\[ \sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2} \]
Therefore, the square root of 128 is:
\[ 8\sqrt{2} \]
So the correct response is:
8 start root 2 end root.