To find the cubic root of \( 96 \), we can express \( 96 \) in terms of its prime factors:
\[ 96 = 2^5 \times 3^1 \]
Next, to find the cubic root, we take the cube root of each factor:
\[ \sqrt[3]{96} = \sqrt[3]{2^5} \times \sqrt[3]{3^1} \]
Calculating each component separately:
\[ \sqrt[3]{2^5} = 2^{5/3} = 2^{1 + 2/3} = 2 \cdot 2^{2/3} = 2 \sqrt[3]{4} \] \[ \sqrt[3]{3^1} = 3^{1/3} \]
Putting them together, we have:
\[ \sqrt[3]{96} = 2 \sqrt[3]{4} \times \sqrt[3]{3} = 2 \sqrt[3]{12} \]
Thus, the cubic root of \( 96 \) can be expressed as:
\[ \sqrt[3]{96} = 2 \sqrt[3]{12} \]
Therefore, the answer to the question is:
\( 2 \sqrt[3]{12} \)