To solve the inequality \( 8 + 2x \leq 20 \), we start by isolating \( x \).
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Subtract 8 from both sides: \[ 2x \leq 20 - 8 \] \[ 2x \leq 12 \]
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Next, divide both sides by 2: \[ x \leq 6 \]
This means that any value of \( x \) less than or equal to 6 will satisfy the inequality \( 8 + 2x \leq 20 \).
Now let's evaluate the given options:
- 10: This value is greater than 6, so it does not satisfy the inequality.
- 8: This value is also greater than 6, so it does not satisfy the inequality.
- 6: This value is equal to 6, so it satisfies the inequality.
- 4: This value is less than 6, so it satisfies the inequality.
Thus, two values from the options that satisfy the inequality \( 8 + 2x \leq 20 \) are 6 and 4.
To explain further:
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For \( x = 6 \): \[ 8 + 2(6) = 8 + 12 = 20 \quad \text{(which is equal to 20, satisfying the inequality)} \]
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For \( x = 4 \): \[ 8 + 2(4) = 8 + 8 = 16 \quad \text{(which is less than 20, satisfying the inequality)} \]
In conclusion, both \( x = 6 \) and \( x = 4 \) satisfy the inequality \( 8 + 2x \leq 20 \).