Question

Use the following formula to solve: A 700-kg vehicle is traveling at a speed of 6 m/s. How much kinetic energy does it have?
*
1 point

12,600 J
50,400 J
700 J

Answer 1

To calculate the kinetic energy (KE) of the vehicle, you can use the formula:

\[
KE = \frac{1}{2} mv^2
\]

where:
- \( m \) is the mass of the object (in kilograms),
- \( v \) is the speed of the object (in meters per second).

Given:
- \( m = 700 \, \text{kg} \)
- \( v = 6 \, \text{m/s} \)

Now plug the values into the formula:

\[
KE = \frac{1}{2} \times 700 \, \text{kg} \times (6 \, \text{m/s})^2
\]

First, calculate \( (6 \, \text{m/s})^2 \):

\[
(6 \, \text{m/s})^2 = 36 \, \text{m}^2/\text{s}^2
\]

Now substitute that back into the equation:

\[
KE = \frac{1}{2} \times 700 \, \text{kg} \times 36 \, \text{m}^2/\text{s}^2
\]

Calculate \( \frac{1}{2} \times 700 \):

\[
\frac{1}{2} \times 700 = 350
\]

Now multiply that by 36:

\[
KE = 350 \, \text{kg} \times 36 \, \text{m}^2/\text{s}^2 = 12600 \, \text{J}
\]

Therefore, the kinetic energy of the vehicle is **12,600 J**.