Use the following formula to solve: A 700-kg vehicle is traveling at a speed of 6 m/s. How much kinetic energy does it have?

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1 point

12,600 J
50,400 J
700 J

1 answer

To calculate the kinetic energy (KE) of the vehicle, you can use the formula:

\[ KE = \frac{1}{2} mv^2 \]

where:

  • \( m \) is the mass of the object (in kilograms),
  • \( v \) is the speed of the object (in meters per second).

Given:

  • \( m = 700 , \text{kg} \)
  • \( v = 6 , \text{m/s} \)

Now plug the values into the formula:

\[ KE = \frac{1}{2} \times 700 , \text{kg} \times (6 , \text{m/s})^2 \]

First, calculate \( (6 , \text{m/s})^2 \):

\[ (6 , \text{m/s})^2 = 36 , \text{m}^2/\text{s}^2 \]

Now substitute that back into the equation:

\[ KE = \frac{1}{2} \times 700 , \text{kg} \times 36 , \text{m}^2/\text{s}^2 \]

Calculate \( \frac{1}{2} \times 700 \):

\[ \frac{1}{2} \times 700 = 350 \]

Now multiply that by 36:

\[ KE = 350 , \text{kg} \times 36 , \text{m}^2/\text{s}^2 = 12600 , \text{J} \]

Therefore, the kinetic energy of the vehicle is 12,600 J.