Question

During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?(1 point)
Responses

20 m/s2
20 m/s2

120 N
120 N

20 N
20 N

-20 N
-20 N

Answer 1

To find the net force of the system, we will consider the forces acting in one direction as positive and those in the opposite direction as negative.

The cue ball is moving to the left with a force of 70 N, which we can assign as positive:
\[ F_{\text{left}} = +70 \, \text{N} \]

The four ball is moving to the right with a force of 50 N, which we will assign a negative value:
\[ F_{\text{right}} = -50 \, \text{N} \]

To find the net force, we add these two forces together:
\[
F_{\text{net}} = F_{\text{left}} + F_{\text{right}} = 70 \, \text{N} + (-50 \, \text{N})
\]
\[
F_{\text{net}} = 70 \, \text{N} - 50 \, \text{N} = 20 \, \text{N}
\]

Thus, the net force of the system is **20 N**.

The correct response is:
**20 N**