To fill in the blanks, we need to manipulate the left side of the equation \((3 + \sqrt{6}) \times 3\).
First, we can distribute the 3:
\[ (3 + \sqrt{6}) \times 3 = 3 \times 3 + \sqrt{6} \times 3 = 9 + 3\sqrt{6} \]
Now we can compare this expression \(9 + 3\sqrt{6}\) with the form \(___ + ___ \times \sqrt{6}\).
From this comparison, we see that:
- The first blank should be \(9\).
- The second blank should be \(3\).
Thus, the completed equation is:
\[ (3 + \sqrt{6}) \times 3 = 9 + 3 \times \sqrt{6} \]
Final answer:
\(9\) and \(3\).