To solve the equation \( x + 11 = -17 \) for \( x \), you should subtract 11 from both sides of the equation.
This will give you:
\[ x + 11 - 11 = -17 - 11 \]
Which simplifies to:
\[ x = -28 \]
So, the correct response is subtract 11.
to solve the value of x
? (1 point).
Responses
subtract 11
subtract 11
add 17
add 17
add 11
add 11
subtract 17
11 answers
To solve the equation \( x + 11 = -17 \) for \( x \), you should subtract 11 from both sides of the equation.
This will give you:
\[ x + 11 - 11 = -17 - 11 \]
Which simplifies to:
\[ x = -28 \]
So, the correct response is subtract 11.
To solve the equation \( x + 23 = 9 \), you need to isolate \( x \). You can do this by subtracting 23 from both sides:
\[ x + 23 - 23 = 9 - 23 \]
This simplifies to:
\[ x = 9 - 23 \] \[ x = -14 \]
So, the solution of the equation is −14.
To determine which equation has a solution of \(-8\), we can substitute \(-8\) into each equation and check if it holds true.
\(x - 8 = 0\): \[ -8 - 8 = -16 \quad \text{(not true)} \]
\(x - 10 = 2\): \[ -8 - 10 = -18 \quad \text{(not true)} \]
\(x - 4 = -12\): \[ -8 - 4 = -12 \quad \text{(true)} \]
\(x + 3 = -11\): \[ -8 + 3 = -5 \quad \text{(not true)} \]
The equation that has a solution of \(-8\) is \(x - 4 = -12\).
To solve the equation \( x - 3.41 = -19 \) for \( x \), you should add 3.41 to both sides of the equation.
This will give you:
\[ x - 3.41 + 3.41 = -19 + 3.41 \]
Which simplifies to:
\[ x = -15.59 \]
So, the correct response is add 3.41.
To determine which equation has a solution of \(-12\), we can substitute \(-12\) into each equation and check if it holds true.
\(x - 12 = 1\): \[ -12 - 12 = -24 \quad \text{(not true)} \]
\(x - 1 = -12\): \[ -12 - 1 = -13 \quad \text{(not true)} \]
\(x + 12 = -1\): \[ -12 + 12 = 0 \quad \text{(not true)} \]
\(x + 1 = 12\): \[ -12 + 1 = -11 \quad \text{(not true)} \]
None of these equations seem to directly yield \(-12\) as a solution by substitution.
However, let's rewrite the first equation to see if one matches:
\(x - 12 = 1\): \ Solving this yields: \[ x = 1 + 12 = 13 \quad \text{(not -12)} \]
\(x - 1 = -12\): \ This yields: \[ x = -12 + 1 = -11 \quad \text{(not -12)} \]
\(x + 12 = -1\): \ This gives: \[ x = -1 - 12 = -13 \quad \text{(not -12)} \]
\(x + 1 = 12\): \ This gives: \[ x = 12 - 1 = 11 \quad \text{(not -12)} \]
It appears none of the provided equations produce \(-12\) as the solution. If there is a different set of equations I'm not seeing or misinterpreting, please verify the options or let me know!
To determine which equation has a solution of \(-\frac{1}{2}\), we can substitute \(-\frac{1}{2}\) into each equation and check if it holds true.
\(x - \frac{1}{2} = 1\): \[ -\frac{1}{2} - \frac{1}{2} = 1 \implies -1 \neq 1 \quad \text{(not true)} \]
\(x - 1 = -\frac{1}{2}\): \[ -\frac{1}{2} - 1 = -\frac{1}{2} \implies -\frac{3}{2} \neq -\frac{1}{2} \quad \text{(not true)} \]
\(x + \frac{1}{2} = -1\): \[ -\frac{1}{2} + \frac{1}{2} = -1 \implies 0 \neq -1 \quad \text{(not true)} \]
\(x + 1 = \frac{1}{2}\): \[ -\frac{1}{2} + 1 = \frac{1}{2} \implies \frac{1}{2} = \frac{1}{2} \quad \text{(true)} \]
The equation that has a solution of \(-\frac{1}{2}\) is \(x + 1 = \frac{1}{2}\).