Question
Use the following formula to solve: A 700-kg vehicle is traveling at a speed of 6 m/s. How much kinetic energy does it have?
*
1 point
kinetic energy = 1/2 mass x speed2
12,600 J
50,400 J
700 J
*
1 point
kinetic energy = 1/2 mass x speed2
12,600 J
50,400 J
700 J
Answers
GPT-4o mini
To calculate the kinetic energy (KE) of the vehicle, we will use the formula:
\[
\text{kinetic energy} = \frac{1}{2} \times \text{mass} \times \text{speed}^2
\]
Given:
- mass = 700 kg
- speed = 6 m/s
Now, substituting the values into the formula:
\[
\text{kinetic energy} = \frac{1}{2} \times 700 \, \text{kg} \times (6 \, \text{m/s})^2
\]
Calculating the speed squared:
\[
(6 \, \text{m/s})^2 = 36 \, \text{m}^2/\text{s}^2
\]
Now, plug this value into the formula:
\[
\text{kinetic energy} = \frac{1}{2} \times 700 \, \text{kg} \times 36 \, \text{m}^2/\text{s}^2
\]
\[
= \frac{1}{2} \times 25200 \, \text{kg} \cdot \text{m}^2/\text{s}^2
\]
\[
= 12600 \, \text{J}
\]
So, the kinetic energy of the vehicle is **12,600 J**.
\[
\text{kinetic energy} = \frac{1}{2} \times \text{mass} \times \text{speed}^2
\]
Given:
- mass = 700 kg
- speed = 6 m/s
Now, substituting the values into the formula:
\[
\text{kinetic energy} = \frac{1}{2} \times 700 \, \text{kg} \times (6 \, \text{m/s})^2
\]
Calculating the speed squared:
\[
(6 \, \text{m/s})^2 = 36 \, \text{m}^2/\text{s}^2
\]
Now, plug this value into the formula:
\[
\text{kinetic energy} = \frac{1}{2} \times 700 \, \text{kg} \times 36 \, \text{m}^2/\text{s}^2
\]
\[
= \frac{1}{2} \times 25200 \, \text{kg} \cdot \text{m}^2/\text{s}^2
\]
\[
= 12600 \, \text{J}
\]
So, the kinetic energy of the vehicle is **12,600 J**.