To solve the quadratic equation \((x + 27)^2 - 6 = -3\), we will first isolate the squared term.
- Add 6 to both sides:
\[ (x + 27)^2 - 6 + 6 = -3 + 6 \]
\[ (x + 27)^2 = 3 \]
- Take the square root of both sides:
\[ x + 27 = \pm \sqrt{3} \]
- Isolate \(x\):
For the positive square root:
\[ x = -27 + \sqrt{3} \]
For the negative square root:
\[ x = -27 - \sqrt{3} \]
- Calculate the numerical values of the solutions:
Using the approximation \(\sqrt{3} \approx 1.732\):
For \(x = -27 + \sqrt{3}\):
\[ x \approx -27 + 1.732 \approx -25.268 \]
For \(x = -27 - \sqrt{3}\):
\[ x \approx -27 - 1.732 \approx -28.732 \]
- Rounding to the nearest hundredth:
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The first solution (the smaller one) rounded is: \[ x \approx -28.73 \]
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The second solution (the larger one) rounded is: \[ x \approx -25.27 \]
- Listing the answers from smallest to largest:
The first solution is \(x = -28.73\)
The second solution is \(x = -25.27\)
Final answers: The first solution is \(x = -28.73\)
The second solution is \(x = -25.27\)