What is the value of y in the following system?y=3x−56x+3y=15(1 point)

Answer 1

To find the value of \( y \) in the given system of equations:

1. The first equation is: \[ y = 3x - 5 \]

2. The second equation is: \[ 6x + 3y = 15 \]

We can substitute the first equation into the second equation.

Substituting \( y \) in the second equation:

\[ 6x + 3(3x - 5) = 15 \]

Now, simplify the equation:

\[ 6x + 9x - 15 = 15 \]

Combine like terms:

\[ 15x - 15 = 15 \]

Add 15 to both sides:

\[ 15x = 30 \]

Now, divide by 15:

\[ x = 2 \]

Now that we have \( x \), we can find \( y \) by substituting \( x = 2 \) back into the first equation:

\[ y = 3(2) - 5 \]

Calculate:

\[ y = 6 - 5 = 1 \]

Thus, the value of \( y \) is

\[ \boxed{1} \]