To analyze the quadratic function \( y = x^2 - 8x \), we can rewrite it in vertex form to identify key points:
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Find the vertex: The vertex of a parabola given by the equation \( y = ax^2 + bx + c \) can be found using the formula: \[ x = -\frac{b}{2a} \] Here, \( a = 1 \), \( b = -8 \), and \( c = 0 \).
Calculate the x-coordinate of the vertex: \[ x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \]
Then, substitute \( x = 4 \) back into the original equation to find the y-coordinate: \[ y = (4)^2 - 8(4) = 16 - 32 = -16 \] Thus, the vertex is at \( (4, -16) \).
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Find the x-intercepts: To find the x-intercepts, set \( y = 0 \): \[ 0 = x^2 - 8x \] Factor the equation: \[ 0 = x(x - 8) \] Setting each factor to zero gives: \[ x = 0 \quad \text{or} \quad x = 8 \] Therefore, the x-intercepts are \( (0, 0) \) and \( (8, 0) \).
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Find the y-intercept: The y-intercept occurs when \( x = 0 \): \[ y = 0^2 - 8 \cdot 0 = 0 \] Thus, the y-intercept is \( (0, 0) \).
Summarizing the key points:
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)
Conclusion
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)
Based on the choices provided:
- The correct listing is:
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)