Asked by Ally

The temperature of 100.0 mL of water was raised from 26.7 degrees C to 62.3 degrees C. How much heat in calories was added to the water? (The specific heat of water is 1.000 cal/g degrees C and the density of water at 26.7 degrees C is 0.996626 g/mL)

Answers

Answered by DrBob222
q = mass water x specific heat water x delta T.
Answered by Anonymous
3560cal
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions