1 answer
(click or scroll down)
To express 108 as a product of prime factors, we can start by dividing it by the smallest prime numbers.
1. Divide by 2 (the smallest prime number):
\( 108 \div 2 = 54 \)
2. Divide 54 by 2 again:
\( 54 \div 2 = 27 \)
3. Now, divide 27 by 3 (the next smallest prime number):
\( 27 \div 3 = 9 \)
4. Divide 9 by 3 again:
\( 9 \div 3 = 3 \)
5. Finally, divide 3 by 3:
\( 3 \div 3 = 1 \)
This gives us the prime factorization of 108 as:
\[
108 = 2^2 \times 3^3
\]
Thus, the product of primes of 108 is:
\[
2^2 \times 3^3
\]