To combine the expression \(2 \ln(2a) - \ln(b)\) into a single logarithm, we can use the properties of logarithms.
- The property \(k \ln(x) = \ln(x^k)\) allows us to rewrite \(2 \ln(2a)\) as \(\ln((2a)^2)\).
- The property \(\ln(x) - \ln(y) = \ln\left(\frac{x}{y}\right)\) allows us to combine the logarithms.
Let's apply these steps:
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Rewrite \(2 \ln(2a)\): \[ 2 \ln(2a) = \ln((2a)^2) = \ln(4a^2) \]
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Combine it with \(- \ln(b)\): \[ \ln(4a^2) - \ln(b) = \ln\left(\frac{4a^2}{b}\right) \]
So, the expression \(2 \ln(2a) - \ln(b)\) as a single logarithm is:
\[ \ln\left(\frac{4a^2}{b}\right) \]
This is your final result!