Question
Rewrite the following expression as a single logarithm.
2 ln left parenthesis 2 a right parenthesis minus ln b
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Part 1
2 ln left parenthesis 2 a right parenthesis minus ln bequals
enter your response here
2 ln left parenthesis 2 a right parenthesis minus ln b
Question content area bottom
Part 1
2 ln left parenthesis 2 a right parenthesis minus ln bequals
enter your response here
Answers
Answered by
GPT-4o mini
To combine the expression \(2 \ln(2a) - \ln(b)\) into a single logarithm, we can use the properties of logarithms.
1. The property \(k \ln(x) = \ln(x^k)\) allows us to rewrite \(2 \ln(2a)\) as \(\ln((2a)^2)\).
2. The property \(\ln(x) - \ln(y) = \ln\left(\frac{x}{y}\right)\) allows us to combine the logarithms.
Let's apply these steps:
1. Rewrite \(2 \ln(2a)\):
\[
2 \ln(2a) = \ln((2a)^2) = \ln(4a^2)
\]
2. Combine it with \(- \ln(b)\):
\[
\ln(4a^2) - \ln(b) = \ln\left(\frac{4a^2}{b}\right)
\]
So, the expression \(2 \ln(2a) - \ln(b)\) as a single logarithm is:
\[
\ln\left(\frac{4a^2}{b}\right)
\]
This is your final result!
1. The property \(k \ln(x) = \ln(x^k)\) allows us to rewrite \(2 \ln(2a)\) as \(\ln((2a)^2)\).
2. The property \(\ln(x) - \ln(y) = \ln\left(\frac{x}{y}\right)\) allows us to combine the logarithms.
Let's apply these steps:
1. Rewrite \(2 \ln(2a)\):
\[
2 \ln(2a) = \ln((2a)^2) = \ln(4a^2)
\]
2. Combine it with \(- \ln(b)\):
\[
\ln(4a^2) - \ln(b) = \ln\left(\frac{4a^2}{b}\right)
\]
So, the expression \(2 \ln(2a) - \ln(b)\) as a single logarithm is:
\[
\ln\left(\frac{4a^2}{b}\right)
\]
This is your final result!
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