Question
The number of psychiatry papers published each year decreases by 7%. if 26,000 papers were published in the current year, how many papers would be expected to be published in 5 years?.(round to nearest whole number)
find a in this equation using y=a(b)^x
find base
find exponential equation
find how many papers are published after 5 years
find a in this equation using y=a(b)^x
find base
find exponential equation
find how many papers are published after 5 years
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the problem, we'll use the formula for exponential decay, which is given by the equation:
\[ y = a(b)^x \]
where:
- \( y \) is the amount after \( x \) years,
- \( a \) is the initial amount,
- \( b \) is the base,
- \( x \) is the number of years.
### Step 1: Identify \( a \) and \( b \)
1. **Initial amount \( a \)**: This is the number of papers published in the current year, which is given as 26,000. Therefore, \( a = 26,000 \).
2. **Base \( b \)**: Since the number of papers published decreases by 7% each year, we can express that as:
\[ b = 1 - 0.07 = 0.93 \]
### Step 2: Write the exponential equation
We can now construct the exponential equation:
\[ y = 26000(0.93)^x \]
### Step 3: Calculate the number of papers published after 5 years
Now, we need to find out how many papers will be published after \( x = 5 \) years. We substitute \( x = 5 \) into the equation:
\[
y = 26000(0.93)^5
\]
Calculating \( (0.93)^5 \):
\[
(0.93)^5 \approx 0.6593
\]
Now substituting this back into the equation:
\[
y \approx 26000 \times 0.6593 \approx 17140.78
\]
### Step 4: Round to the nearest whole number
Finally, rounding to the nearest whole number:
\[
y \approx 17141
\]
### Summary
- **Initial amount (\( a \))**: 26,000
- **Base (\( b \))**: 0.93
- **Exponential equation**: \( y = 26000(0.93)^x \)
- **Number of papers published after 5 years**: **17,141**.
\[ y = a(b)^x \]
where:
- \( y \) is the amount after \( x \) years,
- \( a \) is the initial amount,
- \( b \) is the base,
- \( x \) is the number of years.
### Step 1: Identify \( a \) and \( b \)
1. **Initial amount \( a \)**: This is the number of papers published in the current year, which is given as 26,000. Therefore, \( a = 26,000 \).
2. **Base \( b \)**: Since the number of papers published decreases by 7% each year, we can express that as:
\[ b = 1 - 0.07 = 0.93 \]
### Step 2: Write the exponential equation
We can now construct the exponential equation:
\[ y = 26000(0.93)^x \]
### Step 3: Calculate the number of papers published after 5 years
Now, we need to find out how many papers will be published after \( x = 5 \) years. We substitute \( x = 5 \) into the equation:
\[
y = 26000(0.93)^5
\]
Calculating \( (0.93)^5 \):
\[
(0.93)^5 \approx 0.6593
\]
Now substituting this back into the equation:
\[
y \approx 26000 \times 0.6593 \approx 17140.78
\]
### Step 4: Round to the nearest whole number
Finally, rounding to the nearest whole number:
\[
y \approx 17141
\]
### Summary
- **Initial amount (\( a \))**: 26,000
- **Base (\( b \))**: 0.93
- **Exponential equation**: \( y = 26000(0.93)^x \)
- **Number of papers published after 5 years**: **17,141**.
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