To simplify the expression \((3i + 4)(-2i - 5)\), we will use the distributive property (also known as the FOIL method for binomials).
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First: Multiply the first terms: \[ 3i \cdot (-2i) = -6i^2 \]
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Outer: Multiply the outer terms: \[ 3i \cdot (-5) = -15i \]
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Inner: Multiply the inner terms: \[ 4 \cdot (-2i) = -8i \]
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Last: Multiply the last terms: \[ 4 \cdot (-5) = -20 \]
Now, combine all these results: \[ -6i^2 - 15i - 8i - 20 \]
Combine like terms (\(-15i\) and \(-8i\)): \[ -6i^2 - 23i - 20 \]
Since \(i^2 = -1\), we can substitute that in: \[ -6(-1) - 23i - 20 = 6 - 23i - 20 \]
Combine the real parts: \[ (6 - 20) - 23i = -14 - 23i \]
So, the simplified expression is: \[ \boxed{-14 - 23i} \]