To find the width of the rectangular park, you can use the formula for the area of a rectangle:
\[ \text{Area} = \text{Length} \times \text{Width} \]
You're given that the area is \(1.34 \times 10^8 , \text{ft}^2\) and the length is \(1.6 \times 10^4 , \text{ft}\).
We can rearrange the formula to solve for the width:
\[ \text{Width} = \frac{\text{Area}}{\text{Length}} \]
Substituting in the values:
\[ \text{Width} = \frac{1.34 \times 10^8}{1.6 \times 10^4} \]
Now, dividing the coefficients and the powers of ten separately:
\[ \text{Width} = \frac{1.34}{1.6} \times \frac{10^8}{10^4} \]
Calculating the division of the coefficients:
\[ \frac{1.34}{1.6} \approx 0.8375 \]
And for the powers of ten:
\[ \frac{10^8}{10^4} = 10^{8-4} = 10^4 \]
So, combining these results:
\[ \text{Width} \approx 0.8375 \times 10^4 \]
To express this in standard scientific notation:
\[ 0.8375 \times 10^4 = 8.375 \times 10^3 \]
Therefore, the width of the park is approximately:
\[ \text{Width} \approx 8.375 \times 10^3 , \text{ft} \quad \text{or} \quad 8375 , \text{ft} \]