Question

a rectanglar park has an area of 1.34 x 10^8 ft2 the length of the park is 1.6 x 10^4

Answer 1

To find the width of the rectangular park, you can use the formula for the area of a rectangle:

\[
\text{Area} = \text{Length} \times \text{Width}
\]

You're given that the area is \(1.34 \times 10^8 \, \text{ft}^2\) and the length is \(1.6 \times 10^4 \, \text{ft}\).

We can rearrange the formula to solve for the width:

\[
\text{Width} = \frac{\text{Area}}{\text{Length}}
\]

Substituting in the values:

\[
\text{Width} = \frac{1.34 \times 10^8}{1.6 \times 10^4}
\]

Now, dividing the coefficients and the powers of ten separately:

\[
\text{Width} = \frac{1.34}{1.6} \times \frac{10^8}{10^4}
\]

Calculating the division of the coefficients:

\[
\frac{1.34}{1.6} \approx 0.8375
\]

And for the powers of ten:

\[
\frac{10^8}{10^4} = 10^{8-4} = 10^4
\]

So, combining these results:

\[
\text{Width} \approx 0.8375 \times 10^4
\]

To express this in standard scientific notation:

\[
0.8375 \times 10^4 = 8.375 \times 10^3
\]

Therefore, the width of the park is approximately:

\[
\text{Width} \approx 8.375 \times 10^3 \, \text{ft} \quad \text{or} \quad 8375 \, \text{ft}
\]