Question
Is (
–
1,
–
10) a solution to this system of equations?
y=
–
8x+7
y=6x+5
–
1,
–
10) a solution to this system of equations?
y=
–
8x+7
y=6x+5
Answers
Answered by
GPT-4o mini
To determine if the point \((-1, -10)\) is a solution to the system of equations given by:
1. \(y = -8x + 7\)
2. \(y = 6x + 5\)
we need to substitute \(x = -1\) and \(y = -10\) into both equations.
**For the first equation:**
\[
y = -8x + 7
\]
Substituting \(x = -1\):
\[
y = -8(-1) + 7
\]
\[
y = 8 + 7
\]
\[
y = 15
\]
Since for \(x = -1\), \(y\) should be 15, and we have \(y = -10\), this point does not satisfy the first equation.
**For the second equation:**
\[
y = 6x + 5
\]
Substituting \(x = -1\):
\[
y = 6(-1) + 5
\]
\[
y = -6 + 5
\]
\[
y = -1
\]
Since for \(x = -1\), \(y\) should be -1, and we have \(y = -10\), this point does not satisfy the second equation either.
Since \((-1, -10)\) does not satisfy either equation, it is not a solution to the system of equations.
1. \(y = -8x + 7\)
2. \(y = 6x + 5\)
we need to substitute \(x = -1\) and \(y = -10\) into both equations.
**For the first equation:**
\[
y = -8x + 7
\]
Substituting \(x = -1\):
\[
y = -8(-1) + 7
\]
\[
y = 8 + 7
\]
\[
y = 15
\]
Since for \(x = -1\), \(y\) should be 15, and we have \(y = -10\), this point does not satisfy the first equation.
**For the second equation:**
\[
y = 6x + 5
\]
Substituting \(x = -1\):
\[
y = 6(-1) + 5
\]
\[
y = -6 + 5
\]
\[
y = -1
\]
Since for \(x = -1\), \(y\) should be -1, and we have \(y = -10\), this point does not satisfy the second equation either.
Since \((-1, -10)\) does not satisfy either equation, it is not a solution to the system of equations.