Asked by Quandale dingle
How many solutions are in the solution set for the equation 2x^2 = 20
A. Two
B. Zero
C. One
D. Infinitely many
A. Two
B. Zero
C. One
D. Infinitely many
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the equation \( 2x^2 = 20 \), we can start by simplifying it.
1. Divide both sides by 2:
\[
x^2 = 10
\]
2. Next, take the square root of both sides:
\[
x = \pm\sqrt{10}
\]
This indicates that there are two solutions: \( x = \sqrt{10} \) and \( x = -\sqrt{10} \).
So the number of solutions in the solution set is **two**.
The answer is **A. Two**.
1. Divide both sides by 2:
\[
x^2 = 10
\]
2. Next, take the square root of both sides:
\[
x = \pm\sqrt{10}
\]
This indicates that there are two solutions: \( x = \sqrt{10} \) and \( x = -\sqrt{10} \).
So the number of solutions in the solution set is **two**.
The answer is **A. Two**.
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