Solve for k.

Question

34k+38k=12



Enter the answer, as a whole number or as a fraction in simplest form, in the box.

Answer 1

To solve for $k$ in the equation $34k+38k=12$, first combine the like terms on the left side:

$$34k+38k=(34+38)k=72k$$

Thus, the equation simplifies to:

$$72k=12$$

Next, divide both sides by 72 to isolate $k$:

$$k=\frac{12}{72}$$

Now simplify the fraction:

$$k=\frac{12÷12}{72÷12}=\frac{1}{6}$$

Therefore, the solution for $k$ is

$$\boxed{{\displaystyle \frac{1}{6}}}$$