To find the solution set for the inequalities \(4x - 3 > 9\) and \(x + 6 > -2\), let's solve each inequality individually.
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Solve \(4x - 3 > 9\): \[ 4x - 3 > 9 \] Add 3 to both sides: \[ 4x > 12 \] Divide by 4: \[ x > 3 \]
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Solve \(x + 6 > -2\): \[ x + 6 > -2 \] Subtract 6 from both sides: \[ x > -8 \]
Now, we combine the solutions:
- The first inequality gives us \(x > 3\).
- The second inequality gives us \(x > -8\).
Since \(x > 3\) is the stricter condition, the solution set for the combined inequalities is: \[ {x \mid x > 3} \]
So, the correct response is: \({x \mid x > 3}\) (left brace x vertical bar x greater than 3 right brace).