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Original Question
Find the distance between the points ( – 10, – 8) and ( – 10,14). unitsAsked by Zoey
Find the distance between the points (-10, -8) and (16, -8).
units
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Answered by
GPT-4o mini
To find the distance between the points \((-10, -8)\) and \((16, -8)\), we can use the distance formula, which is given by:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
In this case, the coordinates of the two points are:
- Point 1 \((x_1, y_1) = (-10, -8)\)
- Point 2 \((x_2, y_2) = (16, -8)\)
Now we can plug in the coordinates into the distance formula:
\[
d = \sqrt{(16 - (-10))^2 + (-8 - (-8))^2}
\]
Calculating each part:
1. For \(x\) coordinates:
\[
x_2 - x_1 = 16 - (-10) = 16 + 10 = 26
\]
2. For \(y\) coordinates:
\[
y_2 - y_1 = -8 - (-8) = -8 + 8 = 0
\]
Now substituting back into the distance formula:
\[
d = \sqrt{(26)^2 + (0)^2} = \sqrt{676 + 0} = \sqrt{676} = 26
\]
Therefore, the distance between the points \((-10, -8)\) and \((16, -8)\) is \(\boxed{26}\) units.
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
In this case, the coordinates of the two points are:
- Point 1 \((x_1, y_1) = (-10, -8)\)
- Point 2 \((x_2, y_2) = (16, -8)\)
Now we can plug in the coordinates into the distance formula:
\[
d = \sqrt{(16 - (-10))^2 + (-8 - (-8))^2}
\]
Calculating each part:
1. For \(x\) coordinates:
\[
x_2 - x_1 = 16 - (-10) = 16 + 10 = 26
\]
2. For \(y\) coordinates:
\[
y_2 - y_1 = -8 - (-8) = -8 + 8 = 0
\]
Now substituting back into the distance formula:
\[
d = \sqrt{(26)^2 + (0)^2} = \sqrt{676 + 0} = \sqrt{676} = 26
\]
Therefore, the distance between the points \((-10, -8)\) and \((16, -8)\) is \(\boxed{26}\) units.
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