To solve the quadratic inequality \(x^2 - 4x - 21 > 0\), we first need to factor the quadratic expression.
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Factor the quadratic: We look for two numbers that multiply to \(-21\) (the constant term) and add up to \(-4\) (the coefficient of \(x\)). The numbers that fit are \(-7\) and \(3\).
Thus, we can factor the quadratic as: \[ (x - 7)(x + 3) > 0 \]
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Find the roots: The roots of the equation \(x^2 - 4x - 21 = 0\) are \(x = 7\) and \(x = -3\).
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Analyze the intervals: The roots split the number line into three intervals:
- \( (-\infty, -3) \)
- \( (-3, 7) \)
- \( (7, \infty) \)
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Test the intervals:
- For \(x < -3\) (e.g., \(x = -4\)): \[ (-4 - 7)(-4 + 3) = (-11)(-1) = 11 > 0 \]
- For \(-3 < x < 7\) (e.g., \(x = 0\)): \[ (0 - 7)(0 + 3) = (-7)(3) = -21 < 0 \]
- For \(x > 7\) (e.g., \(x = 8\)): \[ (8 - 7)(8 + 3) = (1)(11) = 11 > 0 \]
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Conclusion:
- The inequality \(x^2 - 4x - 21 > 0\) holds true for the intervals \((-\infty, -3)\) and \((7, \infty)\).
- Therefore, the solution set is: \[ x < -3 \quad \text{or} \quad x > 7 \]
In interval notation, this can be written as: \[ (-\infty, -3) \cup (7, \infty) \]
So, the correct answer from the provided options is: \(x < -3 \text{ or } x > 7\).