What is the solution set to the quadratic inequality x2−4x−21>0 ?(1 point)Responses−3≤x≤7negative 3 is less than or equal to x comma x is less than or equal to 7x≤−3 or x≥7x is less than or equal to negative 3 o r x comma negative 3 o r x is greater than or equal to 7−3<x<7negative 3 is less than x comma x is less than 7x<−3 or x>7

1 answer

To solve the quadratic inequality \(x^2 - 4x - 21 > 0\), we first need to factor the quadratic expression.

  1. Factor the quadratic: We look for two numbers that multiply to \(-21\) (the constant term) and add up to \(-4\) (the coefficient of \(x\)). The numbers that fit are \(-7\) and \(3\).

    Thus, we can factor the quadratic as: \[ (x - 7)(x + 3) > 0 \]

  2. Find the roots: The roots of the equation \(x^2 - 4x - 21 = 0\) are \(x = 7\) and \(x = -3\).

  3. Analyze the intervals: The roots split the number line into three intervals:

    • \( (-\infty, -3) \)
    • \( (-3, 7) \)
    • \( (7, \infty) \)
  4. Test the intervals:

    • For \(x < -3\) (e.g., \(x = -4\)): \[ (-4 - 7)(-4 + 3) = (-11)(-1) = 11 > 0 \]
    • For \(-3 < x < 7\) (e.g., \(x = 0\)): \[ (0 - 7)(0 + 3) = (-7)(3) = -21 < 0 \]
    • For \(x > 7\) (e.g., \(x = 8\)): \[ (8 - 7)(8 + 3) = (1)(11) = 11 > 0 \]
  5. Conclusion:

    • The inequality \(x^2 - 4x - 21 > 0\) holds true for the intervals \((-\infty, -3)\) and \((7, \infty)\).
    • Therefore, the solution set is: \[ x < -3 \quad \text{or} \quad x > 7 \]

In interval notation, this can be written as: \[ (-\infty, -3) \cup (7, \infty) \]

So, the correct answer from the provided options is: \(x < -3 \text{ or } x > 7\).