To solve this problem, we need to set up the equation based on the costs of the sketchbooks and paint sets and ensure their total equals $96.
Let \( x \) be the number of sketchbooks and \( y \) be the number of paint sets. The cost is given by:
\[ 12x + 15y = 96 \]
Now let's evaluate each option:
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2 sketchbooks and 5 paint sets: \[ 12(2) + 15(5) = 24 + 75 = 99 \quad (\text{too much}) \]
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4 sketchbooks and 3 paint sets: \[ 12(4) + 15(3) = 48 + 45 = 93 \quad (\text{too little}) \]
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1 sketchbook and 4 paint sets: \[ 12(1) + 15(4) = 12 + 60 = 72 \quad (\text{too little}) \]
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3 sketchbooks and 4 paint sets: \[ 12(3) + 15(4) = 36 + 60 = 96 \quad (\text{exactly right}) \]
From the calculations, the only combination Alex can purchase, which totals exactly $96, is 3 sketchbooks and 4 paint sets.