You also know that 1 mole SrSO4 gives 1 mole Sr^+2 and 1 mole SO4^-2.
The problem gives you the concn of Sr^+2 as 5 x 10^-4, sulfate is the same, substitute into the expression you wrote for Ksp and you have it.
The molarity of Sr2+ in a saturated solution of SrSO4 was determined to be 0.000500 M. Calculate the solubility product constant (Ksp) for SrSO4.
SrSO4(s) = Sr^2+(aq) + SO4^2- (aq)
Molar Mass (g/mol)
SrSO4 183.68
This is what I know:
Ksp = [Sr][SO4]
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