Question
The molarity of Sr2+ in a saturated solution of SrSO4 was determined to be 0.000500 M. Calculate the solubility product constant (Ksp) for SrSO4.
SrSO4(s) = Sr^2+(aq) + SO4^2- (aq)
Molar Mass (g/mol)
SrSO4 183.68
This is what I know:
Ksp = [Sr][SO4]
SrSO4(s) = Sr^2+(aq) + SO4^2- (aq)
Molar Mass (g/mol)
SrSO4 183.68
This is what I know:
Ksp = [Sr][SO4]
Answers
You also know that 1 mole SrSO4 gives 1 mole Sr^+2 and 1 mole SO4^-2.
The problem gives you the concn of Sr^+2 as 5 x 10^-4, sulfate is the same, substitute into the expression you wrote for Ksp and you have it.
The problem gives you the concn of Sr^+2 as 5 x 10^-4, sulfate is the same, substitute into the expression you wrote for Ksp and you have it.
Related Questions
use the following data, as appropriate, to estimate the molarity of a saturated aqueous solution of...
The Ksp values of BaSO4 and SrSO4 are 1.1x10^-10 and 3.8x10^-7 respectively. Calculate the concentra...
The solubility of lead (II) chloride in water is 4.50 g/L at 25 degrees C
a. What is the molarity...