Question

Three pounds of lawn seed covers 1800 square feet. How many 4 pound bags are needed to cover 8400 square feet?

Answer 1

To determine how many 4-pound bags of lawn seed are needed to cover 8400 square feet, we first need to establish the coverage provided by one 4-pound bag of lawn seed.

From the problem, we know that 3 pounds of lawn seed covers 1800 square feet. Therefore, we can find how much area 1 pound of lawn seed covers:

\[
\text{Area covered by 1 pound} = \frac{1800 \text{ square feet}}{3 \text{ pounds}} = 600 \text{ square feet per pound}
\]

Next, we find out how much area one 4-pound bag covers:

\[
\text{Area covered by a 4-pound bag} = 4 \text{ pounds} \times 600 \text{ square feet per pound} = 2400 \text{ square feet}
\]

Now we will calculate how many 4-pound bags are needed to cover 8400 square feet:

\[
\text{Number of 4-pound bags needed} = \frac{8400 \text{ square feet}}{2400 \text{ square feet per bag}} = 3.5
\]

Since we cannot purchase a fraction of a bag, we must round up to the nearest whole number. Therefore, we need:

\[
\text{Number of bags needed} = 4
\]

Thus, to cover 8400 square feet, **4 four-pound bags** of lawn seed are needed.