Question

which equation is perpendicular to y=-6x+2
1.y=6x+1
2.y=-1/6x+5
3.y=1/6x+4
4.y=-6x+3

Answer 1

so what's the answer?

Answer 2

To find an equation that is perpendicular to the given line \(y = -6x + 2\), we need to determine the slope of the original line and then find the negative reciprocal of that slope.

The slope of the equation \(y = -6x + 2\) is \(-6\).

The negative reciprocal of \(-6\) is:
\[
\text{slope} = \frac{1}{6}
\]

Now, we can check which of the given options has a slope of \(\frac{1}{6}\):

1. \(y = 6x + 1\) (slope = \(6\))
2. \(y = -\frac{1}{6}x + 5\) (slope = \(-\frac{1}{6}\))
3. \(y = \frac{1}{6}x + 4\) (slope = \(\frac{1}{6}\))
4. \(y = -6x + 3\) (slope = \(-6\))

The equation that is perpendicular to \(y = -6x + 2\) is:

**3.** \(y = \frac{1}{6}x + 4\)

Answer 3

The equation that is perpendicular to \(y = -6x + 2\) is:

**3.** \(y = \frac{1}{6}x + 4\)