Question
According to the Law of Conversation of Mass, if 88 g of carbon dioxide (C02) is produced in a reaction between oxygen (O) and 24 g of carbon (C), wgat us the mass of dioxygen (02) in the reactants?
Answers
Answered by
GPT-4o mini
The Law of Conservation of Mass states that mass cannot be created or destroyed in a chemical reaction. Therefore, the total mass of the reactants must equal the total mass of the products.
In this reaction, you have:
- Mass of carbon (C) = 24 g
- Mass of carbon dioxide (CO₂) produced = 88 g
To find the mass of dioxygen (O₂) in the reactants, you can set up the equation:
\[
\text{Mass of reactants} = \text{Mass of products}
\]
Let \( m \) be the mass of dioxygen (O₂):
\[
\text{Mass of carbon (C)} + \text{Mass of dioxygen (O₂)} = \text{Mass of carbon dioxide (CO₂)}
\]
Substituting in the known values:
\[
24 \, \text{g} + m = 88 \, \text{g}
\]
Now, solve for \( m \):
\[
m = 88 \, \text{g} - 24 \, \text{g} = 64 \, \text{g}
\]
Thus, the mass of dioxygen (O₂) in the reactants is **64 grams**.
In this reaction, you have:
- Mass of carbon (C) = 24 g
- Mass of carbon dioxide (CO₂) produced = 88 g
To find the mass of dioxygen (O₂) in the reactants, you can set up the equation:
\[
\text{Mass of reactants} = \text{Mass of products}
\]
Let \( m \) be the mass of dioxygen (O₂):
\[
\text{Mass of carbon (C)} + \text{Mass of dioxygen (O₂)} = \text{Mass of carbon dioxide (CO₂)}
\]
Substituting in the known values:
\[
24 \, \text{g} + m = 88 \, \text{g}
\]
Now, solve for \( m \):
\[
m = 88 \, \text{g} - 24 \, \text{g} = 64 \, \text{g}
\]
Thus, the mass of dioxygen (O₂) in the reactants is **64 grams**.