The equation you've provided, \( 12x + 13y - 2 = 0 \), is a linear equation in two variables (x and y). We can rearrange it into slope-intercept form (\( y = mx + b \)), where \( m \) is the slope and \( b \) is the y-intercept.
To convert the equation into slope-intercept form:
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Start with the given equation: \[ 12x + 13y - 2 = 0 \]
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Isolate \( y \): \[ 13y = -12x + 2 \]
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Divide everything by 13: \[ y = -\frac{12}{13}x + \frac{2}{13} \]
Now the equation is in slope-intercept form where:
- The slope \( m = -\frac{12}{13} \)
- The y-intercept \( b = \frac{2}{13} \)
If you need further information, such as finding specific points on the line or graphing it, let me know!